[Snort-users] What is the last 2 digits in this IP address? 1 126.96.36.199/24
Basselgia, Barry A Mr (NAF Atsugi)
BABasselgia at ...12104...
Mon Mar 14 23:26:44 EST 2005
The last 2 digit are the subnet mask. Here is a quick break down:
Dotted Decimal CIDR
Class a = 255.0.0.0 = /8
Class b = 255.255.0.0 = /16
Class c = 255.255.255.0 = /24
Dotted Decimal and CIDR notation are just different ways of saying the same
thing. The /24 basically means there are 24 bits in the network address,
leaving 8 bits for the host address. Any network subnet calculator should
be able to show both the dotted decimal or the CIDR notation for a subnet
If you want more info on CIDR notation, goggle for it, you get plenty of
From: snort-users-admin at lists.sourceforge.net
[mailto:snort-users-admin at lists.sourceforge.net]On Behalf Of mr
Sent: Tuesday, March 15, 2005 4:07 PM
To: snort-users at lists.sourceforge.net
Subject: [Snort-users] What is the last 2 digits in this IP address?
What is the last 2 digits in this IP address? 192.168.0.0/24
What is 24? How do you calculate or get that digits?
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