[Snort-users] What is the last 2 digits in this IP address? 1 92.168.0.0/24

Basselgia, Barry A Mr (NAF Atsugi) BABasselgia at ...12104...
Mon Mar 14 23:26:44 EST 2005


The last 2 digit are the subnet mask.  Here is a quick break down:
		  Dotted Decimal  CIDR
Class a	= 255.0.0.0     = /8
Class b	= 255.255.0.0   = /16
Class c	= 255.255.255.0 = /24

Dotted Decimal and CIDR notation are just different ways of saying the same
thing.  The /24 basically means there are 24 bits in the network address,
leaving 8 bits for the host address.  Any network subnet calculator should
be able to show both the dotted decimal or the CIDR notation for a subnet
mask.

If you want more info on CIDR notation, goggle for it, you get plenty of
info.

Barry


-----Original Message-----
From: snort-users-admin at lists.sourceforge.net
[mailto:snort-users-admin at lists.sourceforge.net]On Behalf Of mr
leokenzie
Sent: Tuesday, March 15, 2005 4:07 PM
To: snort-users at lists.sourceforge.net
Subject: [Snort-users] What is the last 2 digits in this IP address?
192.168.0.0/24


What is the last 2 digits in this IP address? 192.168.0.0/24
What is 24? How do you calculate or get that digits?

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